Assignment #92 and Heron's Formula

Code

      //Name: Mark Katz
    ///Period: 6
    ///Program Name: Heron's Formula
    ///File Name: herons.java
    ///Date Finished: 11/16/15 
public class herons
{
	public static void main( String[] args )
	{
		double a;
		
		a = triangleArea(3, 3, 3);
		System.out.println("A triangle with sides 3,3,3 has an area of " + a );

		a = triangleArea(3, 4, 5);
		System.out.println("A triangle with sides 3,4,5 has an area of " + a );
 
		a = triangleArea(7, 8, 9);
		System.out.println("A triangle with sides 7,8,9 has an area of " + a );

		System.out.println("A triangle with sides 5,12,13 has an area of " + triangleArea(5, 12, 13) );
		System.out.println("A triangle with sides 10,9,11 has an area of " + triangleArea(10, 9, 11) );
		System.out.println("A triangle with sides 8,15,17 has an area of " + triangleArea(8, 15, 17) );
        System.out.println("A triangle with side 9,9,9 has an area of " + triangleArea(9, 9, 9) );
        // it wasn't difficult because I just followed what the other ones did
	}
 
	public static double triangleArea( int a, int b, int c )
	{
		// the code in this function computes the area of a triangle whose sides have lengths a, b, and c
		double s, A;

		s = (a+b+c) / 2.0;
		A = Math.sqrt( s*(s-a)*(s-b)*(s-c) );

		return A;
		// ^ after computing the area, "return" it
	}
}
//they both produce the same output
//the no function one is 50, while the function one is 30
//it was easier to fix the one with a function because I had to only change it once, not for every single traingle
 
    

Picture of the output